For a cell involving one electron E°Cell = 0.59 V at 298 K, the equilibrium constant for the cell reaction is :[Given that at T = 298 K] A. 1.0 × 105

B. 1.0 × 1010

C. 1.0 × 1030

D. 1.0 × 102

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pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is: A. 0.25 × 10–10

B. 0.125 × 10–15

C. 0.5 × 10–10

D. 0.5 × 10–15

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IIT JEE ADVANCED 2019 FULL VIDEO SOLUTION, CHEMISTRY

IIT JEE ADVANCED 2019 FULL VIDEO SOLUTION, CHEMISTRY

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NEET 2019 THERMOCHEMISTRY SOLUTION

Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1 L bar = 100 J)

A. 5 Kj                B. 25 J          C. 30 J                                 D. –30 J

Answer : -30 joule VIDEO SOLUTION